Let’s say you get a question like this in the exam:
Make a the subject of b(a - ab) + 4(ab + a) = 2b
a) a = b(1 - b) ÷ 2b + 4
b) a = 2b ÷ (b(1 - b) + 4(b + 1))
c) a = (1 - b)(b + 1)
d) a = 2b(1 - b)(b + 4)
To answer this question, we need to get a on its own on one side of the equation.
To begin with, we can take a common factor of a out of the term b(a - ab) to get ab(1 - b).
We do this by dividing both terms by a (a ÷ a = 1, ab ÷ a = b), meaning that (a - ab) = a(1 - b).
Similarly, we can take a common factor of a out of the term 4(ab + a) to get 4a(b + 1). The left hand side of the equation now becomes ab(1 - b) + 4a(b + 1).
Next, we can take a common factor of a out of the entire left hand side of the equation. Both terms are multiplied by a, so if we divide out the a we get a(b(1 - b) + 4(b + 1)).
Our equation now reads a(b(1 - b)+ 4(b + 1)) = 2b.
Finally, since the left hand side of the equation is a term (b(1 - b) + 4(b + 1)) multiplied by a, we can divide both sides of the equation by this term to get a on its own. This gives us a result of a = 2b ÷ (b(1 - b) + 4(b + 1)), which is option (b). To recap:
Watch video for explanation of the following question/s:
The formula for area is l x w (length x width).
Rearrange this formula (A = lw) to solve for l if A = 25 squared cm and width is 15 cm.
Your answer __________
If P = ½yz², rearrange to so that:
y is the subject. Your answer __________
z is the subject. Your answer __________
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